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Plsql program for updating

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This is a complete book on PL/SQL with everything you need to know to write efficient and complex PL/SQL code.

This appendix provides several PL/SQL programs to guide you in writing your own.

This clause can also be extended to lock only the intended table in the SELECT query containing more than one table in joins using the FOR UPDATE OF clause.

This clause becomes meaningless if we use a single table SELECT clause as the minimum Oracle has provided us with the WHERE CURRENT OF clause for both DELETE and UPDATE statements inside a cursor’s range to make changes to the last fetched row(s) from the cursor with an ease.

You can find these scripts in the PL/SQL demo directory.

The first script builds the database tables processed by the sample programs.

On an insert, if the account already exists, an update is done instead. Balance is now: 00.00 ** Debit which account number? SELECT ename, empno, sal FROM emp ORDER BY sal DESC; ENAME EMPNO SAL ---------- --------- -------- KING 7839 5000 SCOTT 7788 3000 FORD 7902 3000 JONES 7566 2975 BLAKE 7698 2850 CLARK 7782 2450 ALLEN 7499 1600 TURNER 7844 1500 MILLER 7934 1300 WARD 7521 1250 MARTIN 7654 1250 ADAMS 7876 1100 JAMES 7900 950 SMITH 7369 800 typedef char asciz; EXEC SQL BEGIN DECLARE SECTION; /* Define type for null-terminated strings.

plsql program for updating-1

Which string is inserted depends on the value of the loop index. -- available online in file 'sample1' DECLARE x NUMBER := 100; BEGIN FOR i IN 1..10 LOOP IF MOD(i,2) = 0 THEN -- i is even INSERT INTO temp VALUES (i, x, 'i is even'); ELSE INSERT INTO temp VALUES (i, x, 'i is odd'); END IF; x := x 100; END LOOP; COMMIT; END; SELECT * FROM temp ORDER BY col1; NUM_COL1 NUM_COL2 CHAR_COL -------- -------- --------- 1 100 i is odd 2 200 i is even 3 300 i is odd 4 400 i is even 5 500 i is odd 6 600 i is even 7 700 i is odd 8 800 i is even 9 900 i is odd 10 1000 i is even SELECT ename, empno, sal FROM emp ORDER BY sal DESC; ENAME EMPNO SAL ---------- --------- -------- KING 7839 5000 SCOTT 7788 3000 FORD 7902 3000 JONES 7566 2975 BLAKE 7698 2850 CLARK 7782 2450 ALLEN 7499 1600 TURNER 7844 1500 MILLER 7934 1300 WARD 7521 1250 MARTIN 7654 1250 ADAMS 7876 1100 JAMES 7900 950 SMITH 7369 800 -- available online in file 'sample2' DECLARE CURSOR c1 is SELECT ename, empno, sal FROM emp ORDER BY sal DESC; -- start with highest paid employee my_ename VARCHAR2(10); my_empno NUMBER(4); my_sal NUMBER(7,2); BEGIN OPEN c1; FOR i IN 1..5 LOOP FETCH c1 INTO my_ename, my_empno, my_sal; EXIT WHEN c1%NOTFOUND; /* in case the number requested */ /* is more than the total */ /* number of employees */ INSERT INTO temp VALUES (my_sal, my_empno, my_ename); COMMIT; END LOOP; CLOSE c1; END; -- available online in file 'sample3' DECLARE x NUMBER := 0; counter NUMBER := 0; BEGIN FOR i IN 1..4 LOOP x := x 1000; counter := counter 1; INSERT INTO temp VALUES (x, counter, 'in OUTER loop'); /* start an inner block */ DECLARE x NUMBER := 0; -- this is a local version of x BEGIN FOR i IN 1..4 LOOP x := x 1; -- this increments the local x counter := counter 1; INSERT INTO temp VALUES (x, counter, 'inner loop'); END LOOP; END; END LOOP; COMMIT; END; SELECT * FROM temp ORDER BY col2; NUM_COL1 NUM_COL2 CHAR_COL -------- -------- ------------- 1000 1 in OUTER loop 1 2 inner loop 2 3 inner loop 3 4 inner loop 4 5 inner loop 2000 6 in OUTER loop 1 7 inner loop 2 8 inner loop 3 9 inner loop 4 10 inner loop 3000 11 in OUTER loop 1 12 inner loop 2 13 inner loop 3 14 inner loop 4 15 inner loop 4000 16 in OUTER loop 1 17 inner loop 2 18 inner loop 3 19 inner loop 4 20 inner loop table contains an account number, an action to be taken (I, U, or D for insert, update, or delete), an amount by which to update the account, and a time tag used to sequence the transactions. The program calls the procedure repeatedly, displaying each batch of employee data, until no more data is found.If the account to */ /* be updated doesn't exist, create a new */ /* account. */ /*----------------------------------------*/ IF acct.oper_type = 'U' THEN UPDATE accounts SET bal = acct.new_value WHERE account_id = acct.account_id; IF SQL%NOTFOUND THEN -- account didn't exist. INSERT INTO accounts VALUES (acct.account_id, acct.new_value); UPDATE action SET status = 'Update: ID not found. When we want to update or delete the cursor fetched row(s) from the database, we don’t have to form In the below code listing, the employees joined before the year 2000 are archived and during the cursor process, no other session is permitted to make any changes to those employees using the FOR UPDATE clause.The employee deletion from the transaction table is performed using the WHERE CURRENT OF clause as shown below.The sample programs illustrate several important PL/SQL concepts and features.